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Home/ Questions/Q 5973067
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T20:44:52+00:00 2026-05-22T20:44:52+00:00

I rewrite a boost.asio example Timer.3 – Binding arguments to a handler. I think

  • 0

I rewrite a boost.asio example “Timer.3 – Binding arguments to a handler”. I think “worker” can work forever and “print” can be called each second. But “print” only is called once. It is very diffcult for me to think why.

If this can’t work,how can I do other things except “async_wait” in one single thread.

#include <iostream>
#include <boost/asio.hpp>
#include <boost/bind.hpp>
#include <boost/date_time/posix_time/posix_time.hpp>

int num = 0;
void worker(){
    while(1){
        ++num;
    }
}
void print(const boost::system::error_code& /*e*/,
    boost::asio::deadline_timer* t, int* count)
{
    std::cout << *count << "\n";
    ++(*count);

    t->expires_at(t->expires_at() + boost::posix_time::seconds(1));
    t->async_wait(boost::bind(
        print, boost::asio::placeholders::error, t, count
    ));
    if(*count == 1){
        worker();
    }
}

int main()
{
    boost::asio::io_service io;

    int count = 0;
    boost::asio::deadline_timer t(io, boost::posix_time::seconds(1));
    t.async_wait(boost::bind(print,
        boost::asio::placeholders::error, &t, &count
    ));
    io.run();

    std::cout << "Final count is " << count << "\n";

    return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T20:44:52+00:00Added an answer on May 22, 2026 at 8:44 pm

    You have an infinite loop

    void worker() {
        while(1) {
            ++num;
        }
    }
    

    so control never returns the first time print() is invoked.

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