Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 5965931
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T19:42:43+00:00 2026-05-22T19:42:43+00:00

I run an XPath in Java with the following xml and code: <?xml version=1.0

  • 0

I run an XPath in Java with the following xml and code:

<?xml version="1.0" encoding="UTF-8"?>
<list>
    <member name="James">
        <friendlist>
            <friend>0001</friend>
            <friend>0002</friend>
            <friend>0003</friend>
        </friendlist>
    </member>
    <member name="Jamie">
        <friendlist>
            <friend>0003</friend>
            <friend>0002</friend>
            <friend>0001</friend>
        </friendlist>
    </member>
    <member name="Katie">
        <friendlist>
            <friend>0001</friend>
            <friend>0003</friend>
            <friend>0004</friend>
        </friendlist>
    </member>
</list>

Code:

try {
    XPath xpath = XPathFactory.newInstance().newXPath();
    XPathExpression pathExpr = xpath.compile("/list/member/friendlist/friend[.='0003']");
} catch (XPathExpressionException e) {

Of course there are more codes after this but I didn’t paste it here because it thought it may confuse even more.

But the idea is I wish to select all the friend nodes that have the ID 0003 from all the members’ friendlist nodes, and then remove it from the XML file. The XPath works by selecting all the “friend” nodes that have the value=0003. I know I can use the removeChild() method of the XML Document object. But the problem is how do I remove all of it directly, without going through layers of loops starting from its parent? The removeChild() method needs me to know its parent’s parent’s parent.

Thanks!

Update:
This is how I used my XPath:

XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression pathExpr = null;
try {
    pathExpr = xpath.compile("/list/member/friendlist/friend[.='0003']");
} catch (XPathExpressionException e) {
    e.printStackTrace();
}
NodeList list = null;
try {
    list = (NodeList) pathExpr.evaluate(xmlDoc, XPathConstants.NODESET);
} catch (XPathExpressionException e) {
    e.printStackTrace();
}

The xmlDoc is an XML document object that has an XML file parsed. The XML works fine. It is only the XML not returning a reference but a whole new nodelist, which makes it impossible for me to refer back to its original xml document to do amendments.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T19:42:45+00:00Added an answer on May 22, 2026 at 7:42 pm

    for each node in the returned NodeList:

    n.getParentNode().removeChild(n);
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Consider the following XSLT script: <?xml version=1.0 encoding=ISO-8859-1?> <xsl:stylesheet version=1.0 xmlns:xsl=http://www.w3.org/1999/XSL/Transform> <xsl:output method=text encoding=iso-8859-1/>
Ive got a large XML set, which I would like to run some xpath
Run the following code, a = [1, 2, 3, 4, 5] head, *tail =
I wrote an app that uses XPath to query some XML config files. When
I'm using Html Agility Pack to run xpath queries on a web page. I
How do I run an XPath query in QT? I need to sort out
I get one array, when i am parsing a xml file using xpath xquery.The
This is starting to piss me off real bad. I have this XML code:
Run this in IE 7,8 or 9. <!DOCTYPE html> <html> <head> <meta charset=utf-8> <title>IE
I run Flex Builder 3 on a mac and as my project grows -

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.