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Home/ Questions/Q 6922713
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:26:30+00:00 2026-05-27T10:26:30+00:00

I saved an original image in my database using the following fields: file_name VARCHAR(255)

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I saved an original image in my database using the following fields:

file_name VARCHAR(255)
mime_type VARCHAR(255)
file_size INT
file_data LONGBLOB

My PHP code for saving is:

$image = $_FILES['image'];
$info = getImageSize($image['tmp_name']);
$query = "CALL saveImageInDataBase('" .        
    mysql_real_escape_string(file_get_contents($image['tmp_name'])) . "', '" . 
    mysql_real_escape_string($image['name']) . "', '" . 
    mysql_real_escape_string($info['mime']) . "', " . $image['size'] . ")";
$result = mysql_query($query);

I want to create a thumbnails of original images out of above data in the server (I’m using PHP) in order to display on the site (to display a list of links of images).

Can someone tell me the simplest way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:26:31+00:00Added an answer on May 27, 2026 at 10:26 am

    You are doing the whole thing wrong.

    1. DO NOT store images in the database. It makes absolutely no sense in the context of an HTML-drven website.
    2. DO NOT create thumbnails on the fly. Create them right after upload and store in the files along with original image.

    For the particular code you may search either google or this site. There are over 100500 codes written already I believe.

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