Question

I saw in this post that I could use the below example to define a default controller/page

@RequestMapping(value={"/content/edit", "/"}, method=RequestMethod.GET)

Unfortunately it’s not working. When I open my app it shows a 404 error unless I look for /content/edit.htm

my web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/applicationContext.xml</param-value>
    </context-param>
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>
    <servlet>
        <servlet-name>Spring-MVC-Dispatcher-Servlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/app-config.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>Spring-MVC-Dispatcher-Servlet</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>
</web-app>

Answer 1

Your servlet is mapped to “*.htm”. “/” does not match that pattern, so your servlet and thus your controller has no chance of being invoked. I think you can specify the welcome file (that’s what / is) in web.xml, I would have to look up how, though.