Question

I saw some examples in java where they do synchronization on a block of code to change some variable while that variable was declared volatile originally .. I saw that in an example of singleton class where they declared the unique instance as volatile and they sychronized the block that initializes that instance … My question is why we declare it volatile while we synch on it, why we need to do both?? isn’t one of them is sufficient for the other ??

public class SomeClass {
    volatile static Object uniqueInstance = null;

    public static Object getInstance() {
        if (uniqueInstance == null) {
            synchronized (someClass.class) {
                if (uniqueInstance == null) {
                    uniqueInstance = new SomeClass();
                }
            }
        }
        return uniqueInstance;
    }
}

thanks in advance.

Answer 1

Synchronization by itself would be enough in this case if the first check was within synchronized block (but it’s not and one thread might not see changes performed by another if the variable were not volatile). Volatile alone would not be enough because you need to perform more than one operation atomically. But beware! What you have here is so-called double-checked locking – a common idiom, which unfortunately does not work reliably. I think this has changed since Java 1.6, but still this kind of code may be risky.

EDIT: when the variable is volatile, this code works correctly since JDK 5 (not 6 as I wrote earlier), but it will not work as expected under JDK 1.4 or earlier.