Question

I saw the following program on the internet

public class Test1{
 public static void main(String[] args)
 {
 Integer int1 = new Integer(10);
 Vector vec1 = new Vector();
 LinkedList list = new LinkedList();
 vec1.add(int1);
 list.add(int1);
 if(vec1.equals(list)) System.out.println("equal");
 else  System.out.println("not equal");
  }

}

The answer it print is “equal”.

How it is possible?

Thanks

Dilip

Answer 1

Because both a LinkedList and Vector implement List#equals()

Returns true if and only if the specified object is also a list, both
lists have the same size, and all corresponding pairs of elements in
the two lists are equal. (Two elements e1 and e2 are equal if
(e1==null ? e2==null : e1.equals(e2)).) In other words, two lists are
defined to be equal if they contain the same elements in the same
order. This definition ensures that the equals method works properly
across different implementations of the List interface.

Specifically, here is the exact reason for this behavior.

This definition ensures that the equals method works properly across different implementations of the List interface.