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Home/ Questions/Q 8614131
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T05:03:04+00:00 2026-06-12T05:03:04+00:00

I saw this problem online, and I was trying to solve it in C++

  • 0

I saw this problem online, and I was trying to solve it in C++. I have the following algorithm:

char permutations( const char* word ){

  int size = strlen( word );
  if( size <= 1 ){
      return word;
  }
  else{
    string output = word[ 0 ];
    for( int i = 0; i < size; i++ ){
        output += permutations( word );
        cout << output << endl;
        output = word[ i ];
     }
  }
  return "";
}

For example, if I have abc as my input, I want to display abc, acb, bac, bca, cab, cba.
So, what I’m trying to do is

'abc' => 'a' + 'bc' => 'a' + 'b' + 'c'
                    => 'a' + 'c' + 'b'

so I need o pass a word less char every function call.
Could someone please help how to do it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T05:03:05+00:00Added an answer on June 12, 2026 at 5:03 am

    I suggest doing it using the algorithm header library in C++, much easier; and as a function can be written like this:

    void anagram(string input){
        sort(input.begin(), input.end());
        do
            cout << input << endl;
        while(next_permutation(input.begin(), input.end()));
    }
    

    However since you want it without the STL, you can do it like so:

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    
    void swap (char *x, char *y)
    {
        char ch = *x;
        *x = *y;
        *y = ch;
    };
    
    void permutate_(char* str, size_t index )
    {
        size_t i = 0;
        size_t slen = strlen(str);
        char lastChar = 0;
    
        if (index == slen )
        {
            puts(str);
            return;
        }
    
        for (i = index; i < slen; i++ )
        {
            if (lastChar == str[i])
                continue;
            else
                lastChar = str[i];
    
            swap(str+index, str+i);
            permutate_(str, index + 1);
            swap(str+index, str+i);
        }
    }
    
    // pretty lame, but effective, comparitor for determining winner
    static int cmpch(const void * a, const void * b)
    {
        return ( *(char*)a - *(char*)b );
    }
    
    // loader for real permutor
    void permutate(char* str)
    {
        qsort(str, strlen(str), sizeof(str[0]), cmpch);
        permutate_(str, 0);
    }
    

    Which you can call by sending it a sorted array of characters,

    permutate("Hello World");
    

    The non-STL approach was gotten from here.

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