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Home/ Questions/Q 6098287
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T13:08:28+00:00 2026-05-23T13:08:28+00:00

I searched the same thing on net and got many answers but some how

  • 0

I searched the same thing on net and got many answers but some how dint get working with any of them.

Table:

  1. Report: reportType(foreign key from ReportCategory), name, description
  2. Report Category: name, description

forms.py

class ReportForm_insert(forms.ModelForm):    
        class Meta:    
        model=Report  
        invent = ReportCategory.objects.all()  
        print invent  
        reportType_id = forms.ModelMultipleChoiceField(queryset = invent)   
        fields =('name','description',)

model.py

class ReportCategory(models.Model):  
       name = models.CharField(max_length=20)  
    description =  models.CharField(max_length=20)

    def __unicode__(self):
        return self.name

class Report(models.Model):   
    reportType = models.ForeignKey(ReportCategory)
    name = models.CharField(max_length=200)  
    description = models.CharField(max_length=300)

    def __unicode__(self):
        return self.name

Now, inside the meta class I am trying to do two things:

Firstly, populating the Report Type dropdown box with the value from
the ‘name’ column of ReportCategory table.
Secondly, when all the other fields in the form are filled by the user
and the button is pressed, the data in the fields should be saved in
the Report table keeping in mind the foreign key constraint it has
from the ReportCategory table.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T13:08:28+00:00Added an answer on May 23, 2026 at 1:08 pm

    In forms.py

    class ReportForm_insert(forms.ModelForm):  
        class Meta:  
            model=Report
    

    That is it. Django automatically understands that a drop down has to be created when we declare it as a Foreign key in the model.

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