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Home/ Questions/Q 1073199
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T20:57:45+00:00 2026-05-16T20:57:45+00:00

I see examples for this all over, but for some reason, mine isn’t working.

  • 0

I see examples for this all over, but for some reason, mine isn’t working. I have a textbox that is added dynamically if a certain value is selected in a select list.

The part where the field shows up is working, but I am also trying to add some text to the box, which I can’t get to work. I’m also trying to use JS to select the text once it’s entered – but haven’t gotten that far yet!

Is there something blatantly wrong with this?

function showBox() {
  if (document.getElementById("ctl00_Content_WhereFound").value == "Other" || document.getElementById("ctl00_Content_WhereFound").value == "Friend/Employee Referral") 
  {
    document.getElementById('ctl00_Content_WhereDetails').style.display = "inline";
    if (document.getElementById("ctl00_Content_WhereFound").value == "Other") {
      document.getElementById('ctl00_Content_WhereDetails').innerHTML += 'Enter Other';
    } else {
      document.getElementById('ctl00_Content_WhereDetails').innerText += "Enter Referral";
    }
  }
}
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  1. Editorial Team
    Editorial Team
    2026-05-16T20:57:45+00:00Added an answer on May 16, 2026 at 8:57 pm

    try this..

    function showBox()
    {
        $Found = document.getElementById("ctl00_Content_WhereFound");
        $Where = document.getElementById('ctl00_Content_WhereDetails');
    
        if($Found.value == "Other" || $Found.value == "Friend/Employee Referral")
        {
            $Where.style.display = "inline";
            if($Where.value == "Other")
            {
                $Where.value = 'Enter Other';
            }else
            {
                 $Where.value = "Enter Referral";
            }
        }
    }
    

    You can always assign elements to variables to shorten your code.

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