Question

I see in my code I’m not passing the re-scaled image into the InputStream, I’m passing in the original file-base. Is it possible to pass in newImage in some way as its of a different type?

I’m using MVC2 .NET 3.5

Here’s the controller for uploading:

[HttpPost]
public ActionResult ImageUpload(HttpPostedFileBase fileBase, PhotoViewModel photoViewModel)
{
    if (photoViewModel.Button == "Upload")
    {
        photoViewModel.ImageValid = "Valid";
        ImageService imageService = new ImageService();

        if (fileBase != null && fileBase.ContentLength > 0 && fileBase.ContentLength <= 2097152 && fileBase.ContentType.Contains("image/"))
        {
            Path.GetExtension(fileBase.ContentType);
            var extension = Path.GetExtension(fileBase.FileName);

            if (extension.ToLower() != ".jpg" && extension.ToLower() != ".gif") // only allow these types
            {
                photoViewModel.ImageValid = "Not Valid";
                ModelState.AddModelError("Photo", "Wrong Image Type");
                return View(photoViewModel);
            }
            EncoderParameters encodingParameters = new EncoderParameters(1);
            encodingParameters.Param[0] = new EncoderParameter(Encoder.Quality, 100L); // Set the JPG Quality percentage

            ImageCodecInfo jpgEncoder = imageService.GetEncoderInfo("image/jpeg");
            var uploadedimage = Image.FromStream(fileBase.InputStream, true, true);

            Bitmap originalImage = new Bitmap(uploadedimage);
            Bitmap newImage = new Bitmap(originalImage, 274, 354);

            Graphics g = Graphics.FromImage(newImage);
            g.InterpolationMode = InterpolationMode.HighQualityBilinear;
            g.DrawImage(originalImage, 0, 0, newImage.Width, newImage.Height);

            var streamLarge = new MemoryStream();
            newImage.Save(streamLarge, jpgEncoder, encodingParameters);

            var fileExtension = Path.GetExtension(extension);
            string newname;
            if (photoViewModel.photoURL != null)
            {
                newname = photoViewModel.photoURL;
            }
            else
            {
                newname = Guid.NewGuid() + fileExtension;
            }

            //changed this up now, so it stores the image in db as apposed to physical path
            photoViewModel.photo = newname;
            photoViewModel.ContentType = fileBase.ContentType;
            Int32 length = fileBase.ContentLength;
            byte[] tempImage = new byte[length];
            fileBase.InputStream.Read(tempImage, 0, length);
            photoViewModel.ImageData = tempImage;          

            TempImageUpload tempImageUpload = new TempImageUpload();
            tempImageUpload.TempImageData = tempImage;
            tempImageUpload.ContentType = photoViewModel.ContentType;

            photoViewModel.TempImageId = _service.InsertImageDataBlob(tempImageUpload);

            originalImage.Dispose();
            streamLarge.Dispose();
            return View(photoViewModel);
        }

        if (fileBase != null)
        {
            if (fileBase.ContentLength > 0) ModelState.AddModelError("Photo", "Image size too small");
            if (fileBase.ContentLength <= 2097152) ModelState.AddModelError("Photo", "Image size too big");
            if (fileBase.ContentType.Contains("image/")) ModelState.AddModelError("Photo", "Wrong Image Type");
        }
        else ModelState.AddModelError("Photo", "Please upload a image");

        if (!ModelState.IsValid)
        {
            photoViewModel.ImageValid = "Not Valid";
            return View(photoViewModel);
        }
    }
    return View(photoViewModel);
}

Here’s my repository class:

public int InsertImageDataBlob(TempImageUpload tempImageUpload)
{
  int ReturnedPhotoId;

  try
  {
    var phototempdata = new Photo
             {
                  ImageData = tempImageUpload.TempImageData,
                  contentType = tempImageUpload.ContentType,
                  dateUploaded = DateTime.Now
             };
    _db.Photos.InsertOnSubmit(phototempdata);
    Save();
    ReturnedPhotoId = phototempdata.id;
    return ReturnedPhotoId;
  }
  catch (Exception ex)
  {
    //ErrorLogging;
  }
  return 0;
}

And image data field (image type) in the database gets populated with data.

Answer 1

I actually got it to work with this code:

      photoViewModel.photo = newname;
      photoViewModel.ContentType = fileBase.ContentType;
      streamLarge.Position = 0;
      byte[] tempImage = new byte[streamLarge.Length + 1];
      streamLarge.Read(tempImage, 0, tempImage.Length);
      photoViewModel.ImageData = tempImage;