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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T21:39:23+00:00 2026-06-05T21:39:23+00:00

I see this notation, a new operator with a class name and then bracketed

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I see this notation, a new operator with a class name and then bracketed code, occasionally in Android examples. Can someone explain this? In the example below, PanChangeListener is a class (or maybe an interface) and ‘new’ creates an instance, but what role does the bracketed code play with respect to the PanChangeListener?

fType pcListener = new PanChangeListener() {

      @Override
      public void onPan(GeoPoint old, GeoPoint current) {
                         //TODO
      }
});

Even a name for this syntax would be useful, as I could Google it.

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  1. Editorial Team
    Editorial Team
    2026-06-05T21:39:24+00:00Added an answer on June 5, 2026 at 9:39 pm

    That’s an anonymous class.

    The syntax allows you to create a new class, provide an implementation for some methods, then instantiate it.

    When a local class is used only once, consider using anonymous class syntax, which places the definition and use of the class in exactly the same place.

    It works in a similar way to the following code that doesn’t use an anonymous class:

    class MyPanChangeListener implements PanChangeListener()
    {
        @Override
        public void onPan(GeoPoint old, GeoPoint current) {
            //TODO
        }
    }
    
    // ...
    
    fType pcListener = new MyPanChangeListener();
    
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