Question

I seem to have a syntax error and can’t see it myself, could someone run over it for me please?

Thanks.

<script>
    var acurl_<?php echo $request_data['friendship_id']; ?> = "sn-include/create_bond_accept.php?friendship_id=<?php echo $request_data['friendship_id']; ?>&friend_id=<?php echo $fromuser['id']; ?>";
</script>

Answer 1

David, on the bright side, you don’t have a syntax error.

If you’re developing PHP, I would recommend two things:

1. Get a better IDE. Dreamweaver is TERRIBLE for working with PHP. I recommend NetBeans (it’s awesome and free).
2. Start breaking up your code into chunks. The big ball of html and PHP is hard to debug.

Check this out:

<?php
    // prepare output
    $segment  = '?friendship_id=' . $request_data['friendship_id'];
    $segment .= '&friend_id=' . $fromuser['id'] . '";' . "\n";

    $acurl  = 'var acurl_' . $request_data['friendship_id'];
    $acurl .= ' = "sn-include/create_bond_accept.php';
    $acurl .= $segment;

    $dnurl  = 'var dnurl_' . $request_data['friendship_id'];
    $dnurl .= ' = "sn-include/create_bond_deny.php';
    $dnurl .= $segment;
?>
<script type="text/javascript">
    <?php
        echo $acurl;
        echo $dnurl;
    ?>
</script>