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Home/ Questions/Q 6676121
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T03:56:50+00:00 2026-05-26T03:56:50+00:00

I seem to have the right syntax but i keep getting a NaN value,

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I seem to have the right syntax but i keep getting a NaN value, i believe it has something to do with the propagation of the array, please could you check the code and see where i am going wrong.

var _array = new Array();

var _first = 1;
var _second = 4;

$('#con > div').each(function(index){

    var _data = $(this).css('left').split('px')[0];
    var _class = $(this).attr('class').split(' ')[0];

    _array[_first] = [_data];
    //_array[_second] = _class;

    _first++;
    _second++;

    if(index == 2){
        _first = 1;
        _second = 4;

        for(var i = 0; i < _array.length; i++)
        console.log(_array[i]);

        var large = Math.max.apply(Math, _array);
        console.log(large);

    }
});

Thanks

http://jsfiddle.net/LTMbr/1/

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  1. Editorial Team
    Editorial Team
    2026-05-26T03:56:50+00:00Added an answer on May 26, 2026 at 3:56 am

    So, I modified it a bit to see – http://jsfiddle.net/LTMbr/4/ and your _array[0] is undefined. So that’s why your call to Math.max is returning NaN.

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