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Home/ Questions/Q 586329
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T15:05:46+00:00 2026-05-13T15:05:46+00:00

I seem to have this pattern occuring pretty often in my code, with two

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I seem to have this pattern occuring pretty often in my code, with two functions performing the same task apart from the constness of their parameters/returns.

int& myClass::getData()
{
        return data;
}

// called for const objects 
const int& myData::getData() const
{
        return data;
}

This offends my sense of DRY. It’s not a problem for a one-liner, but as getData() gets bigger, there’s obvious duplication.

I know WHY I need both methods, but feel there should be a better way to implement it. Is there a template trick that can help, or should I have one method which calls the other casting the constness back and forth as required?

ADDED: As a more real-world example, here’s a sample of typical STL vector::at() implementation:

const_reference at(size_type _Off) const
    {   // subscript nonmutable sequence with checking
    if (size() <= _Off)
        _Xran();
    return (*(begin() + _Off));
    }

reference at(size_type _Off)
    {   // subscript mutable sequence with checking
    if (size() <= _Off)
        _Xran();
    return (*(begin() + _Off));
    }
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  1. Editorial Team
    Editorial Team
    2026-05-13T15:05:46+00:00Added an answer on May 13, 2026 at 3:05 pm

    Use the following trick (which I originally got from Scott Meyers’ book Effective C++):

    int& myClass::getData()
    {
        // This is safe because we know from out here
        // that the return value isn't really const
        return const_cast<int&>(const_cast<const myClass&>(*this).getData());
    }
    
    const int& myData::getData() const
    {
        return data;
    }
    

    Obviously for a short function like this, you may find it easier just to duplicate code, but this idiom is useful when you have a longer function (like vector<T>::at or it is subject to lots of changes.

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