Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 813317
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T01:20:20+00:00 2026-05-15T01:20:20+00:00

I seem to run into so many issues when dealing with writing to directories.

  • 0

I seem to run into so many issues when dealing with writing to directories. If someone could please look over this script, and tell me why it’s not working, I’d be so appreciative.

Upon uploading the file from the form, I don’t get anything.. It doesnt output any errors, it simply just refreshes.

Thanks, Lea

<?php include ('config.php');
 if( isset($_POST['submit']) ) {

$target = ''.$_SERVER['DOCUMENT_ROOT'].'/images/';
$target = $target . basename( $_FILES['photo']['name']) ;
$url = basename( $_FILES['photo']['name']) ;

if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) {
$moved =  "File has been moved to location $target";

$name = mysql_real_escape_string($_POST['photoname']);
mysql_query("INSERT INTO photos (photo_name, photo_image) VALUES ('$name',  '$url' )") or die(mysql_error());
$success = "Photo has been added!";

  } else {

$moved = "File has not been moved to $target";
$success = "Failed to upload:(";

  }

} ?>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"> 
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Photo Upload</title>
<meta name="robots" content="index, follow" />
<meta name="keywords" content="" />
<meta name="description" content="" />
<link href="<?php echo $globalurl; ?>styles.css" rel="stylesheet" type="text/css" />
</head>
<body>
<div class="holder">
<br /><br />
<b>Add a new photo</b>
<hr />
<br />
<b><?php echo "$success<br />"; ?>
<?php echo "$moved<br />"; ?></b>
  <form enctype="multipart/form-data" method="post" action="<?php echo $PHP_SELF; ?>">
    <table cellspacing="0" cellpadding="0" width="500px">
      <tbody>
        <tr>
          <td valign="top">Photo Name:</td>
          <td valign="top">
            <input type="text" name="photoname" /><br />
            <br />
            </td>
        </tr>
        <tr>
          <td valign="top">Photo:</td>
          <td valign="top">
  <input type="file" name="photo"><br />
            <br />
            </td>
        </tr>
      </tbody>
    </table>
    <input type="submit" value="submit" />
  </form>
</div>
</body>
</html>
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-15T01:20:21+00:00Added an answer on May 15, 2026 at 1:20 am

    Without checking the PHP code for errors, the first thing that stands out is that this:

    isset($_POST['submit'])
    

    always returns false. The input type=”submit” must have the name attribute “submit” in order to be sent:

    <input type="submit" value="submit" name="submit" />
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I seem to run into this situation quite a lot and have yet to
I have run into this issue too many times and need this to be
Seem to run into a service endpoint not found problem when trying to get
I've run into another problem in Qt, I can't seem to figure out how
So the problem I've run into is pretty basic, but I can't seem to
I've inherited a hibernate application and I've run into issues. It seems that the
I seem to run into a couple of design issue a lot and I
I run next code and I miss somthing, for me it seem OK :
Why do Scalar-valued functions seem to cause queries to run cumulatively slower the more
Hi I'm trying to run a calculation but I can't seem to put it

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.