Question

I send a pointer to an array of char* to a function (args). In that function I set the value to the first two postions in the array to malloc’d strings. When I return to the orignal calling function where the array itself was malloc’d, the last position of the array gives me a “Cannot access memory at address 0x0”. Am I doing somthing wrong in malloc/realloc/ or storing the values?

Calling Function:

int bufspace = 0; /* bytes in table */

    ...

args = emalloc(BUFSIZ); /* initialize array */
bufspace = BUFSIZ;     //size=8192
spots = BUFSIZ / sizeof(char *);

while (*cp != '\0') //While not at the end
    cp = read_segment(cp, &len, &indollarsign, &argnum, start, &args, &prev_char_escape);
    start = cp;
    len = 0;

    if (argnum + 1 >= spots) {
        args = erealloc(args, bufspace + BUFSIZ);
        bufspace += BUFSIZ;
        spots += (BUFSIZ / sizeof(char *));
        }
    }

Called Function (read_segment) – First called to store at position 0 then at position 1:

*args[*argnum] = newstr(start, *len); //Generate the string through malloc

At this line, I have strings in these positions: *args[0] and *args[1]

But as soon as I return to the calling function
args[0] has a string but args[1] shows a “Cannot access memory at address 0x0”

Answer 1

*args[*argnum] dereferences the pointer at args[*argnum]. I think you meant

(*args)[*argnum] = newstr(start, *len);