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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T04:18:00+00:00 2026-05-26T04:18:00+00:00

I set these up at the beginning of the script: var grid = $(‘#grid’);

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I set these up at the beginning of the script:

var grid = $('#grid');
var lines = $('#lines');
var background = $('#background');

Elsewhere in the script, I need to change the CSS for all 3 elements at the same time. Rather than doing this:

grid.css({...
lines.css({...
background.css({...

I want to do something like one of these:

$(grid, lines, background).css({...
$([grid, lines, background]).css({...

However, the only thing that seems to work is by referencing the IDs directly, like this:

$('#grid, #lines, #background').css({

I’d prefer to use references to the elements instead of the IDs directly, as they may change dynamically. Is this possible?

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  1. Editorial Team
    Editorial Team
    2026-05-26T04:18:01+00:00Added an answer on May 26, 2026 at 4:18 am

    Use .add():

    grid.add(lines).add(background).css({...});
    

    Demo: http://jsfiddle.net/mattball/xj5bb/

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