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Home/ Questions/Q 8390989
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T19:08:26+00:00 2026-06-09T19:08:26+00:00

I should compare some application’s versions using Perl. And the problem is, that the

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I should compare some application’s versions using Perl. And the problem is, that the last part of every version can be set by numbers as well as by alphabetically corresponding letters, that is:

12.3a == 12.31
12.3b == 12.32
12.3c <> 12.34

I saw the version module but it seems to deal only with numbers and underlines.
Maybe I should use overload?
What is the best and most elegant solution?

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  1. Editorial Team
    Editorial Team
    2026-06-09T19:08:27+00:00Added an answer on June 9, 2026 at 7:08 pm

    That’s a weird spec. Normalisation is probably the way to go.

    use version qw( qv );
    
    sub normalise_version {
        my ($v) = @_;
        $v =~ s/([a-i])/ ord($1)-ord('a')+1 /eg;
        return qv("v$v");
    }
    
    normalise_version($v1) <=> normalise_version($v2)
    

    With the above 12.3 is considered smaller than 12.31. Let me know if that’s wrong.

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