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I showed this code to my friend
$user->attempts++; // the attempts property returns an int
and he was like saying how stupid that code was, rambling that numeric operators will produce syntax errors when attached to objects; the thing is it worked as I expected it to (increment attempts by 1, oh yeah, I tested it)
and so I ask, why the hell is this working?
It works because it makes sense.
$user->attemptsis a integer. Forget that it’s attached to an object; it’s an integer. If++didn’t work, I’d be surprised.However, I often find that PHP syntax doesn’t work as I expect, and that it’s fixed in a future version. It’s the sort of thing where one would typically expect it to work but, given personal experience with PHP, may have lowered one’s expectations. Perhaps this is what your friend is feeling.