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Home/ Questions/Q 351099
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T11:36:43+00:00 2026-05-12T11:36:43+00:00

I simply try to assign a background color to each div. it looks simple

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I simply try to assign a background color to each div.
it looks simple but it doesn’t work.

var divElements = $("div");
var colorArray =["444", "344", "345", "472", "837", "043", "345", "472", "837", "043"];

for (var i=0; i< divElements.length; i++){
divElements[i].css("background","#"+colorArray[i])
}

I also tried to use jQuery’s each

$("div").each(function(i) {
  divElements[i].css("background","#"+colorArray[i])
})

How do code this in javaScript generic “for loop” and jQuerys .each()

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T11:36:43+00:00Added an answer on May 12, 2026 at 11:36 am
    $("div").each(function(i, val) {
      $(this).css("background", "#" + colorArray[i]);
    });
    

    You have to watch out for exceeding the bounds of colorArray though (ie if you get too many divs). Possibilities include stopping when you hit the max:

    $("div").each(function(i, val) {
      if (i > colorArray.length) {
        return false; // breaks $.each() loop
      }
      $(this).css("background", "#" + colorArray[i]);
    });
    

    or cycle through them:

    $("div").each(function(i, val) {
      $(this).css("background", "#" + colorArray[i & colorArray.length]);
    });
    

    Not sure why you’d want to do it as Javascript but:

    var divElements = document.getElementsByTagName("div");
    var colorArray =["444", "344", "345", "472", "837", "043", "345", "472", "837", "043"];
    for (var i=0; i< divElements.length; i++){
      divElements[i].style.backgroundColor = '#' + colorArray[i];
    }
    
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