Question

I simply write this:

char* test="test";
printf("%s",test[0]);

it says seg fault;
then I change to
printf("%s",&test[0]); the error gone
But this is not what I want;
the console print: “test ”
how to get just value “t” from that pointer?

Answer 1

If you want just the t, you should do:

printf("%c",test[0]);

The format %c, will print a single char.

%s will print the entire null-terminated string.