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Home/ Questions/Q 4031442
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:35:52+00:00 2026-05-20T11:35:52+00:00

I so miss jQuery. I’m working on a project where I need to get

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I so miss jQuery. I’m working on a project where I need to get my hands dirty with good ‘ol plain Javascript again.

I have this scenario:

parent
    child1
    child2
    child3

Via javascript, I want to be able to insert a new node before or after any of those children. While javascript has an insertBefore, there is no insertAfter.

Insert before would work fine on the above to insert a node before any one of those:

parent.insertBefore(newNode, child3)

But how does one insert a node AFTER child3? I’m using this at the moment:

for (i=0,i<myNodes.length,i++){
    myParent.insertBefore(newNode, myNodes[i+1])
}

That is inserting my newNode before the next sibling node of each of my nodes (meaning it’s putting it after each node).

When it gets to the last node, myNodes[i+1] become undefined as I’m now trying to access a array index that doesn’t exist.

I’d think that’d error out, but it seems to work fine in that in that situation, my node is indeed inserted after the last node.

But is that proper? I’m testing it now in a few modern browsers with no seemingly ill effects. Is there a better way?

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:35:53+00:00Added an answer on May 20, 2026 at 11:35 am

    The functionality of insertBefore(newNode, referenceNode) is described as:

    Inserts the specified node before a reference node as a child of the current node. If referenceNode is null, then newNode is inserted at the end of the list of child nodes.

    And since myNodes[i+1] is outside of the array bounds, it returns undefined, which is treated as null in this case. This means you get your desired behavior.

    Edit: Link to the W3 specification of insertBefore()

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