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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:08:06+00:00 2026-05-15T19:08:06+00:00

I started making this simple google chrome extension in javascript. And in the beginning

  • 0

I started making this simple google chrome extension in javascript. And in the beginning of the code I have the following:

var req = new XMLHttpRequest();

req.open(
    "GET",
    "http://www.ldoceonline.com/dictionary/manga",
    true);

req.onreadystatechange(alert(req.readyState));

The value req.readyState comes to be 1, which means the required page has not been properly fetched. I’m a newbie to Javascript. What’s the problem in my code?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:08:07+00:00Added an answer on May 15, 2026 at 7:08 pm

    how about something like this

    var request = new XMLHttpRequest();
    
    if (request == null){
            alert("Unable to create request");
        }else{
    
            var url = "http://www.ldoceonline.com/dictionary/manga";
    
            request.onreadystatechange = function()
                {
                if(request.readyState == 4)
                {
                    LDResponse(request.responseText);
                }
            }
    
            request.open("GET", url, true);
            request.send(null);
        }
    
    function LDResponse(response)
    {
    // do stuff with the response
    }
    

    Of course this is all assuming that they are giving you valid data back ie XML or json

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