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Home/ Questions/Q 398957
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T16:47:58+00:00 2026-05-12T16:47:58+00:00

I started to learn jQuery. I wrote a code, that will cycle the position

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I started to learn jQuery. I wrote a code, that will cycle the position of an given element by calling functions stored in an array. This works fine for this code:

<script type="text/javascript">
 $(document).ready(function(){
    $('#right_column').css({zIndex:1000, position: 'absolute', right: 0, top:200 });
    $('body').css({overflow:'hidden'});
    var funcs = new Array(
                    function(o){
                        $(o).animate({right: 0, top:200}, 1000);
                    },
                    function(o){
                        $(o).animate({top: 0},1000);
                    },
                    function(o){
                        $(o).animate({right: 300},1000);
                    },
                    function(o){
                        $(o).animate({right: 300, top:200},1000);
                    }
                );
    var flip=0;
    $('#right_column').click(function self(){
            funcs[++flip % funcs.length]('#right_column');
    });
 });
</script>

but if I change the positions parameter like this

    var funcs = new Array(
                    function(o){
                        $(o).animate({right: 0, top:200}, 1000);
                    },
                    function(o){
                        $(o).animate({top: 0},1000);
                    },
                    function(o){
                        $(o).animate({left: 0},1000);
                    },
                    function(o){
                        $(o).animate({right: 300, bottom:0},1000);
                    }
                );

it breaks.

I assume, that the complementary parameters (top<->bottom; left<->right) interfere, as they would do in plain css as well.

So my question is: How can I reset css parameters to undefined?

edit

animate doesn’t seem to be able to handle auto probably. It didn’t change the behavior.
with css() it works.

    var funcs = new Array(
                    function(o){
                        $(o).css({right:0, bottom:0,left:'auto', top:'auto'})
                        console.log('funcs 0');
                    },
                    function(o){
                        $(o).css({top:0, right:0, left:'auto', bottom:'auto'})
                        console.log('funcs 1');
                    },
                    function(o){
                        $(o).css({left:0, top:0, right:'auto', bottom:'auto'})
                        console.log('funcs 2');
                    },
                    function(o){
                        $(o).css({right:'auto', top:'auto',left:0, bottom:0})
                        console.log('funcs 3');
                    }   
                );

running css({...:'auto'}) before/after animate() destroyed (of cause) the animation

any other hint?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T16:47:58+00:00Added an answer on May 12, 2026 at 4:47 pm

    to reset those values change them to ‘auto’

    top: auto;
    left: auto;
    right: 0px;
    bottom: 0px;
    

    Edit:

    You could add “targets”.

     <div id="top" style="position:absolute;left:0;top:0"></div>
     <div id="bottom" style="position:absolute;left:0;top:auto;bottom:0px"></div>
    

    Now you can use the values of your targets for your animation:

    $("#bottom").offset().top
    $("#bottom").offset().left
    

    Animation:

     $(o).animate({ top : $("#bottom").offset().top, left : $("#bottom").offset().left });
    
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