Question

I studied that during initialization of object, for example

string s = "Hello world";

If RHS is implicitly convertible to LHS type object, then Copy Constructor would be called. But I have a friend who is pretty sure that constructor which takes char pointer as an argument would be called.But I told him that constructor with charpointer would be called only in cases as below

string s("Hello world");

Is that correct?

Answer 1

Doing

string s = "Hello world";

is equivalent to

string s( string( "Hello world" ) );

so both the constructor taking char const* and the copy-constructor are called. However, the standard allows copy-elision where the copy-constructor call is elided (not done).