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Home/ Questions/Q 6823843
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T21:49:54+00:00 2026-05-26T21:49:54+00:00

I tend to obsess about expressing code the most compactly and succinctly possible without

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I tend to obsess about expressing code the most compactly and succinctly possible without sacrificing runtime efficiency.

Here’s my code:

p_audio = plate.parts.filter(content__iendswith=".mp3") 
p_video = not p_audio and plate.parts.filter(content__iendswith=".flv") 
p_swf =   not p_audio and not p_video and plate.parts.filter(content__iendswith=".swf") 
extra_context.update({
  'p_audio':  p_audio and p_audio[0],
  'p_video':  p_video and p_video[0],
  'p_swf':    p_swf and   p_swf[0]
})

Are there any python/django gurus that can drastically shorten this code?

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  1. Editorial Team
    Editorial Team
    2026-05-26T21:49:54+00:00Added an answer on May 26, 2026 at 9:49 pm

    Besides featuring less redundancy, this is also way easier to extend with new content types.

    kinds = (("p_audio", ".mp3"), ("p_video", ".flv"), ("p_swf", ".swf"))
    extra_context.update((key, False) for key, _ in kinds)
    
    for key, ext in kinds:
        entries = plate.parts.filter(content__iendswith=ext)
        if entries:
            extra_context[key] = entries[0]
            break
    
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