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Home/ Questions/Q 9248453
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T09:56:53+00:00 2026-06-18T09:56:53+00:00

I tested the following code: (function(){ var x = false; function x(){ return true;

  • 0

I tested the following code:

(function(){
  var x = false;  
  function x(){
    return true;
  }  
  return typeof x;
})();

It returns “boolean”. And only when I comment the second line:

(function(){
  //var x = false;  
  function x(){
    return true;
  }  
  return typeof x;
})();

It returns “function”.
It means that if someone has declared a variable somewhere in the code before, my function declaration using the same name will fail, right? Please, someone explain it to me.
Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T09:56:55+00:00Added an answer on June 18, 2026 at 9:56 am

    In JavaScript, function declarations are treated as if they were written first. Then variable declarations. (That particular ordering matters very rarely, if ever.)

    In variable declarations, any assignment part is treated as a separate expression statement occurring at the point in the function where the var statement actually appears. Thus:

    function foo() {
      // ... some code ...
      if (whatever) {
        var x = whatever + 1;
      }
    }
    

    is treated like:

    function foo() {
      var x;
      // ... some code ...
      if (whatever) {
        x = whatever + 1;
      }
    }
    

    Thus overall your first sample is treated as if it were:

    (function() {
      function x() {
        return true;
      }
      var x;
      x = false;
      return typeof x;
    })();
    

    Note also that functions and variables share a common namespace. A var declaration without an assignment part for a variable name that’s already been declared has no effect. (At least, I think it has no meaningful effect, but JavaScript has weird dark corners …)

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