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Home/ Questions/Q 6114079
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T14:55:57+00:00 2026-05-23T14:55:57+00:00

I think I need to use an alternation construct but I can’t get it

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I think I need to use an alternation construct but I can’t get it to work. How can I get this logic into one regular expression pattern?

match = Regex.Match(message2.Body, @"\r\nFrom: .+\(.+\)\r\n");
if (match.Success)
    match = Regex.Match(message2.Body, @"\r\nFrom: (.+)\((.+)\)\r\n");
else
    match = Regex.Match(message2.Body, @"\r\nFrom: ()(.+)\r\n");

EDIT:

Some sample cases should help with your questions

From: email

and

From: name(email)

Those are the two possible cases. I’m looking to match them so I can do

string name = match.Groups[1].Value;
string email = match.Groups[2].Value;

Suggestions for a different approach are welcome!
Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T14:55:58+00:00Added an answer on May 23, 2026 at 2:55 pm

    This is literally what you’re asking for: "(?=" + regex1 + ")" + regex2 + "|" + regex3

    match = Regex.Match(message.Body, @"(?=\r\nFrom: (.+\(.+\))\r\n)\r\nFrom: (.+)\((.+)\)\r\n|\r\nFrom: ()(.+)\r\n");
    

    But I don’t think that’s really what you want.

    With .net’s Regex, you can name groups like this: (?<name>regex).

    match = Regex.Match(message.Body, @"\r\nFrom: (?<one>.+)\((?<two>.+)\)\r\n|\r\nFrom: (?<one>)(?<two>.+)\r\n");
    
    Console.WriteLine (match.Groups["one"].Value);
    Console.WriteLine (match.Groups["two"].Value);
    

    However, your \r\n is probably not right. That would be a literal rnFrom:. Try this instead.

    match = Regex.Match(message.Body, @"^From: (?:(?<one>.+)\((?<two>.+)\)|(?<one>)(?<two>.+))$");
    
    Console.WriteLine (match.Groups["one"].Value);
    Console.WriteLine (match.Groups["two"].Value);
    
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