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Home/ Questions/Q 1103613
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:22:00+00:00 2026-05-17T01:22:00+00:00

I think I’m getting a scoping error when using transformBy(), part of the doBy

  • 0

I think I’m getting a scoping error when using transformBy(), part of the doBy package for R. Here is a simple example of the problem:

> library(doBy)
>
> test.data = data.frame(
+  herp = c(1,2,3,4,5),
+  derp = c(2,3,1,3,5)
+ )
>
> transformData = function(data){
+ 
+  five = 5
+ 
+  transformBy(
+   ~ herp,
+   data=data,
+   sum=herp + derp + five
+  )
+ }
>
> transformData(test.data)
Error in eval(expr, envir, enclos) : object 'five' not found

When I run transformBy() within a sub-scope (non-global scope) no local variables or functions seem to be available for use in transformBy. If, on the other hand, I define those variables or functions globally, they become available. Here is a slightly modified example that works:

> library(doBy)
>
> test.data = data.frame(
+  herp = c(1,2,3,4,5),
+  derp = c(2,3,1,3,5)
+ )
>
> five = 5
>
> transformData = function(data){
+  transformBy(
+   ~ herp,
+   data=data,
+   sum=herp + derp + five
+  )
+ }
>
> transformData(test.data)
  herp derp sum
1    1    2   8
2    2    3  10
3    3    1   9
4    4    3  12
5    5    5  15

Am I misunderstanding something about how transformBy is supposed to work or is something broken?

Versions:

  • ubuntu: 8.04 (x64)
  • R: 2.10.1
  • doBy: 4.0.5
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T01:22:01+00:00Added an answer on May 17, 2026 at 1:22 am

    This is clearly documented in the ?transformBy help page, and therefore
    not a bug.

    Details:

     The ... arguments are tagged vector expressions, which are
     evaluated in the data frame data. The tags are matched against
     names(data), and for those that match, the value replace the
     corresponding variable in data, and the others are appended to
     data.
    

    Simply make the object “five” a part of the data.frame “data”, and
    it will work as you expect. Currently the function is trying to
    evaluate “five” in the “data” data.frame, which fails of course.

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