Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8948997
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 15, 20262026-06-15T13:08:09+00:00 2026-06-15T13:08:09+00:00

I think I’m missing something fundamental about password based data encryption. A tool that

  • 0

I think I’m missing something fundamental about password based data encryption.

A tool that cracks password hash based login authentication knows it’s found the correct password (or an alternate password that still matches the hash) when it successfully logs in. But how does a tool that cracks file or stream based encryption using a password as the source for a key know when it’s successful? It seems to me that different attempted passwords would turn an encrypted source stream into a different set of destination bytes, with a particular password generating the ‘correct’ set of bytes. I don’t understand how a cracking tool would recognize that it had the correct unencrypted set of bytes, stop trying and report ‘Cracked!’.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-15T13:08:10+00:00Added an answer on June 15, 2026 at 1:08 pm

    Most of the time the plain text uses a known pattern. If it would be fully randomized then the attacker cannot distinguish between success and failure. It could be that a set of keys may be returned, of which only one is correct. That said, most plain text contains enough information (like a longer piece of English text) to distinguish a correct key from the wrong one.

    Furthermore, the encryption mode may leak enough information to distinguish between the plain text and random text. Block cipher modes – such as ECB and CBC – in particular may use some kind of plain text padding. This padding is added before block encryption, and generally contains identifiable information. Take a look at the PKCS#5/7 padding mode for instance.

    Note that encryption algorithms themselves are required to even withstand known plain text attacks, so finding the key should be impossible even if you already know what the decrypted text looks like. However, using passwords weakens the amount of valid keys for modern cryptographic ciphers, so the strength of the password is of utmost importance.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Think about doing this: import matplotlib.pyplot as plt plt.plot(x_A,y_A,'g--') plt.plot(x_B,y_B,'r-o') plt.show() How would you
Think about the following: Your ISP offers you a dynamic ip-address (for example 123.123.123.123).
I think that handlers in android are tools to get different objects that are
I think I have a basic understanding of this, but am hoping that someone
Think google have a limitation for user , so users have to login to
Think you are the proud owner of Facebook, then which data you want to
Think of the following code: static int Main() { byte[] data = File.ReadAllBytes(anyfile); SomeMethod(data);
Think that I have many activities,and all I want is this: I have a
Think that says it all?
Think about a speedometer, and imagine all these little strokes around it like 10

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.