Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 454793
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 12, 20262026-05-12T22:18:23+00:00 2026-05-12T22:18:23+00:00

I think I’m pretty close on this query, but can’t seem to crack it,

  • 0

I think I’m pretty close on this query, but can’t seem to crack it, and I’m not sure if I’ve got the most efficient approach.

I am trying to find a day where a user is not booked from a range of dates where they are booked.

Think staff scheduling. I need to find who is available to work on Tuesday, and is working on other days this week.

My query currently looks like this

SELECT employees.uid, name, date
FROM employees
LEFT JOIN storelocation ON employees.uid = storelocation.uid
LEFT JOIN schedule ON emplyees.uid = schedule.uid
WHERE slid =9308
AND date
BETWEEN '2009-11-10'
AND '2009-12-20'
AND NOT
EXISTS (

SELECT uid
FROM schedule
WHERE date = '2009-11-11'
)

If I don’t include the ‘Not Exists’, I get 1500 results
If I use only the Select form the ‘Not Exists’, I get 200 results, so both of those queries work independently.
However, my query as I’ve written it returns 0 results.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-12T22:18:23+00:00Added an answer on May 12, 2026 at 10:18 pm

    You might want to try something more like this:

    SELECT employees.uid, name, date
    FROM users
    LEFT JOIN storelocation ON employees.uid = storelocation.uid
    LEFT JOIN schedule ON emplyees.uid = schedule.uid
    WHERE slid =9308
    AND date BETWEEN '2009-11-10' AND '2009-12-20'
    AND employees.uid NOT IN (
        SELECT uid
        FROM schedule
        WHERE date = '2009-11-11'
    )
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I think this has probably been asked, but after reading a lot, I'm not
I think this should be pretty simple, but I'm a SQL newb. I have
I think I've seen this answer, but I can't remember where for certain. I'm
I think I have a basic understanding of this, but am hoping that someone
I think this could be a very easy question for you. But I have
I think that asking this might be kind of silly but I'm still wondering
i think this should be very easy , but i really don't know how
I think most people know how to do this via the GUI (right click
I think this is specific to IE 6.0 but... In JavaScript I add a
Think this is my target key in registry: [HKEY_CURRENT_USER\System\Majid\0] GUID=hex:60,de,2a,56,51,b2,e0,11,80,01,44,45,53,54,00,00 as you can see

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.