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Home/ Questions/Q 6559137
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T13:17:09+00:00 2026-05-25T13:17:09+00:00

I think it’s a fairly simple question, but I can’t figure out how to

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I think it’s a fairly simple question, but I can’t figure out how to do this properly.

I’ve got an empty arraylist:

ArrayList<object> list = new ArrayList<object>();

I’ve got some objects In which I want to add object and each object has to be at a certain position. It is necessary however that they can be added in each possible order. When I try this, it doesn’t work and I get an IndexOutOfBoundsException:

list.add(1, object1)
list.add(3, object3)
list.add(2, object2)

What I have tried is filling the ArrayList with null and then doing the above. It works, but I think it’s a horrible solution. Is there another way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-25T13:17:09+00:00Added an answer on May 25, 2026 at 1:17 pm

    You can do it like this:

    list.add(1, object1)
    list.add(2, object3)
    list.add(2, object2)
    

    After you add object2 to position 2, it will move object3 to position 3.

    If you want object3 to be at position3 all the time I’d suggest you use a HashMap with position as key and object as a value.

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