Question

I think its pretty self explanatory from the code. Obviously I’m no evaluating the same thing over and over, its just example numbers to explain my problem. I’m guessing its over/underflow but I don’t know how to deal with it.

double d = (1 / (684985+157781));

System.out.println(d); // returns 0.0
System.out.println(Math.log(d)); // returns -Infinity.

Answer 1

(1 / (684985+157781)) is an integer expression, so it will come out to 0.
The zero then gets assigned to the double d, as 0.0.

Try changing the 1 to 1.0 to force that expression to be a float, or 1.0D to force it to double.