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Home/ Questions/Q 772441
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T18:48:14+00:00 2026-05-14T18:48:14+00:00

I think I’ve got an understanding problem of GTK. My simple application has a

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I think I’ve got an understanding problem of GTK. My simple application has a stream of images and I’d like to display them within my GTK Window. Up to now, it looks like this:

GdkPixbuf *pb = gdk_pixbuf_new_from_data(img2, GDK_COLORSPACE_RGB, 
                     FALSE, 24/3, 320, 240, 320*3,
                     NULL, NULL);
if(pb == NULL)
    fprintf(stderr, "Pixbuf is null!\n");

if(image != NULL)
    gtk_container_remove(GTK_CONTAINER(window), image);
image = gtk_image_new_from_pixbuf(pb);
gtk_container_add(GTK_CONTAINER(window), image);

printf("Updated!\n");

img2 is my (rgb) buffer that gets updated from a stream each time. I guess gtk_container_remove and gtk_container_add might be stupid to use for this?

Here’s what I’ve got in addition:

GtkWidget *window;
GtkWidget *image;

gtk_init(&argc, &argv);

window = gtk_window_new(GTK_WINDOW_TOPLEVEL);

gtk_signal_connect(GTK_OBJECT(window), "destroy",
           GTK_SIGNAL_FUNC(destroy), NULL);

    /* ... */
    start_routine_for_stream_that_calls_the_above(...)
    /* ... */

gtk_widget_show_all(window);
gtk_main();

My problem is that it’s not working this way… either I see only the last GdkPixbuf image or I see none, which is the correct behaviour …

But how do I manage it to show an (stream of) updated GdkPixbuf?

Thanks for help

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  1. Editorial Team
    Editorial Team
    2026-05-14T18:48:14+00:00Added an answer on May 14, 2026 at 6:48 pm

    You need to be running the main loop while you change the images. For instance, you can do gtk_main() and use g_timeout_add() to schedule your callback to run say every second and replace images within that callback.

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