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Home/ Questions/Q 7568775
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T15:00:31+00:00 2026-05-30T15:00:31+00:00

I think my question title is already crystal clear. I am invoking Process.Start() method

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I think my question title is already crystal clear.

I am invoking Process.Start() method by passing, “cmd.exe” as parameter. But somehow when I execute the program the command prompt that appeared has my .../bin/debug/ in my project folder as its directory. I wanted it to change to C: instead.

Can someone advise me on this?

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  1. Editorial Team
    Editorial Team
    2026-05-30T15:00:32+00:00Added an answer on May 30, 2026 at 3:00 pm

    This is the proper way to set a specified working directory for any kind of process:

    var processStartInfo = new ProcessStartInfo();
    processStartInfo.WorkingDirectory = @"c:\";
    processStartInfo.FileName = "cmd.exe";
    
    // set additional properties     
    Process proc = Process.Start(processStartInfo);
    
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