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Home/ Questions/Q 8991245
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T22:40:55+00:00 2026-06-15T22:40:55+00:00

I think the code is self-explanatory: MyClass* pointer = NULL; changePointer( pointer ); if

  • 0

I think the code is self-explanatory:

MyClass* pointer = NULL;
changePointer( pointer );
if (pointer == NULL) 
{
   // it's entering here :(
}



    void changePointer( MyClass* p)
    {
        MyClass* temp = NULL;
        for (int i = 0; i < myContainer.size(); ++i) 
        {
            p = &(myContainer[i]);

            if (p == NULL) 
            {
                 // it's not entering here :)
            }
        }
    }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T22:40:57+00:00Added an answer on June 15, 2026 at 10:40 pm

    The pointer is being passed by value, not by reference, so the original variable cannot be changed. You need to change the function signature to:

    void changePointer(MyClass** p)
    

    …and pass a pointer to the pointer:

    changePointer(&pointer);
    

    You’ll need to make some corresponding changes in the body of the function, too.

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