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Home/ Questions/Q 6598299
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T18:19:41+00:00 2026-05-25T18:19:41+00:00

I think this is a very simple question. but unfortunately I cannot find a

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I think this is a very simple question. but unfortunately I cannot find a solution.
I have a mysql database table called “Invoice” having “inv_No”,”inv_netvalue”,”inv_date” inv_No is the primary key. I want to get a Invoice object according to a given inv_No. I used a critaria. But this result nothing. list.size() is 0.

        Invoice invoice = new Invoice();
        invoice.setInvNo(Integer.parseInt(invoiceNo));
        Session session = HSession.getSession();
        Criteria crit = session.createCriteria(Invoice.class);
        crit.add(Example.create(invoice));
        List list=crit.list();

but when I used this "FROM Invoice invoice WHERE invoice.invNo='" + invoiceNo + "'" it returns which I expected.

Any one help me please.Let me know where I am wrong..

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  1. Editorial Team
    Editorial Team
    2026-05-25T18:19:42+00:00Added an answer on May 25, 2026 at 6:19 pm

    It’s not clear to me why you’ve got the second createCriteria call. Have you tried this?

     Criteria crit = session.createCriteria(Invoice.class);
     crit.add(Example.create(invoice));
    

    That follows some of the examples in the docs, for example.

    EDIT: Another option is not to use “query by example” but just:

     Criteria crit = session.createCriteria(Invoice.class);
     crit.add.(Restrictions.eq("invNo", Integer.parseInt(invoiceNo)));
    
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