Question

I think this must be easy but I do not get it.

Assume I have the following arparse parser:

import argparse

parser = argparse.ArgumentParser( version='pyargparsetest 1.0' )
subparsers = parser.add_subparsers(help='commands')

# all
all_parser = subparsers.add_parser('all', help='process all apps')

# app
app_parser = subparsers.add_parser('app', help='process a single app')
app_parser.add_argument('appname', action='store', help='name of app to process')

How can I identify, which subparser was used?
calling:

print parser.parse_args(["all"])

gives me an empty namespace:

Namespace()

Answer 1

Edit: Please see quornian’s answer to this question, which is better than mine and should be the accepted answer.

According to the argparse documentation the result of parser.parse_args(...) will “only contain attributes for the main parser and the sub parser that was selected”. Unfortunately this may not be enough information to determine which sub parser was used. The documentation recommends using the set_defaults(...) method on the sub parser to solve this problem.

For example, I’ve added calls to set_defaults() to your code:

import argparse

parser = argparse.ArgumentParser( version='pyargparsetest 1.0' )
subparsers = parser.add_subparsers(help='commands')

# all
all_parser = subparsers.add_parser('all', help='process all apps')
all_parser.set_defaults(which='all')

# app
app_parser = subparsers.add_parser('app', help='process a single app')
app_parser.add_argument('appname', action='store', help='name of app to process')
app_parser.set_defaults(which='app')

Now if you run

print parser.parse_args(["all"])

The result is

Namespace(which='all')

Check out the add_subparsers() documentation for more information and another example.