Home/ Questions/Q 7037761
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-28T01:35:03+00:00

I this assembly code: INT %ebx GCC is giving me an error when trying

  • 0

I this assembly code:

INT %ebx

GCC is giving me an error when trying to assemble it:

INT ERROR:mismatch operand type for 'int'.

Does this imply that the operand of instruction INT must be a constant like INT $0X80?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Your assumption is correct, the operand of INT must be a constant. According to the NASM x86 reference:

    A.81 INT: Software Interrupt
INT imm8                      ; CD ib                [8086]

A.82 INT3, INT1, ICEBP, INT01: Breakpoints
INT1                          ; F1                   [P6] 
ICEBP                         ; F1                   [P6] 
INT01                         ; F1                   [P6]
INT3                          ; CC                   [8086]

A.83 INTO: Interrupt if Overflow
INTO                          ; CE                   [8086]

    So INT takes an 8bit immediate value and non of the interrupt variants actually take an register.

    • 0