Question

I thought I had this figured out, but can’t get it working correctly:

All I want is the following:
onChange of either of these dropdowns take the selected value and add it to the hiddentext field [in the actual app, these dropdowns are in a fieldset and only one or the other is displayed based on product type selected] Simple I know, but I can’t see what I am doing wrong.

Code below and my jsFiddle is here: http://jsfiddle.net/justmelat/M3hyX/

<form method="post" action="">
<fieldset name="projInfo" id="projInfo">
                <legend>Proj Info</legend>
                Hidden Product Field:  <input name="hiddenProdField" id="hiddenProdField" type="text" />
                            </fieldset>

<fieldset name="Group1" id="Group1">
                <legend>Product 1</legend>
                <select name="firstSet"  id="firstSet">
                <option value="0">Select</option>
                <option value="One">One</option>
                <option value="Two">Two</option>
                <option value="Three">Three</option>
            </select>
            </fieldset>
<fieldset name="Group2" id="Group2">
                <legend>Product 2</legend>
                <select name="secondSet"  id="secondSet">
                <option value="0">Select</option>
                <option value="Four">Four</option>
                <option value="Five">Five</option>
                <option value="Six">Six</option>
            </select>
            </fieldset>
<fieldset name="Group3" id="Group3">
                <legend>Product 3</legend>
                <select name="thirdSet"  id="thirdSet">
                <option value="0">Select</option>
                <option value="Seven">Seven</option>
                <option value="Eight">Eight</option>
                <option value="Nine">Nine</option>
            </select>
            </fieldset>
</form>​

$(document).ready(function() {
        $("select#firstSet, select#secondSet, select#thirdSet").change(function(){
            var prodType = "";
            $("select#firstSet, select#secondSet, select#thirdSet option:selected");
            prodType = $(this).text();
          $("#hiddenProdField").text(prodType);
        })
        .trigger('change');
    });

Answer 1

$('fieldset select').change(function() {
 $('input#hiddenProdField').val(this.value);
});

DEMO