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Home/ Questions/Q 8739653
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T10:58:41+00:00 2026-06-13T10:58:41+00:00

I thought I understood how to do this but I’m getting some unexpected behavior

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I thought I understood how to do this but I’m getting some unexpected behavior so apparently I’m missing something. Here’s the problem boiled down.

Base Class:

public abstract class Base<T>
{
    abstract public void foo(List<? extends T> l);
}

Derived Class:

public class Derived<T> extends Base
{
    @Override
    public void foo(List<? extends T> l) { return; }
}

The Base class complies fine, but when I compile the Derived class I get:

Derived.java:3: Derived is not abstract and does not override abstract method foo(java.util.List) in Base

public class Derived extends Base
^
Derived.java:5: method does not override or implement a method from a supertype

@Override  
^  

2 errors

The generics of the parameter List<? extends T> appears to be the cause of the problem. If I replace that part in both signatures with the basic type int it comples fine.

Can anybody tell me what’s going on here?

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  1. Editorial Team
    Editorial Team
    2026-06-13T10:58:42+00:00Added an answer on June 13, 2026 at 10:58 am

    You should do

    public class Derived<T> extends Base<T>
    

    You need to specify <T> for Base otherwise you will have to override method by simply declaring List i.e.without generics

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