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Home/ Questions/Q 859961
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T08:44:52+00:00 2026-05-15T08:44:52+00:00

I thought that doing @f def g(): print ‘hello’ is exactly the same as

  • 0

I thought that doing

@f
def g():
   print 'hello'

is exactly the same as

def g():
   print 'hello'
g=f(g)

But, I had this code, that uses contextlib.contextmanager:

@contextlib.contextmanager
def f():
    print 1
    yield
    print 2
with f:
    print 3

which works and yields 1 3 2

And when I tried to change it into

def f():
    print 1
    yield
    print 2
f=contextlib.contextmanager(f)
with f:
    print 3

I get AttributeError: 'function' object has no attribute '__exit__'

What am I missing? is there some black magic specifically in contextlib.contextmanager, or do i misunderstand how decorators work in general?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T08:44:53+00:00Added an answer on May 15, 2026 at 8:44 am

    Yes, decorator is exactly same as calling a function and assigning to returned value

    In this case error comes because you are not calling function, so correct code would be

    def f():
        print 1
        yield
        print 2
    
    f=contextlib.contextmanager(f)
    with f():
        print 3
    

    also I am not sure if you tested code, because decorator code you have given will fail due to same reason

    @contextlib.contextmanager
    def f():
        print 1
        yield
        print 2
    with f:
        print 3
    

    Error:

        with f:
    AttributeError: 'function' object has no attribute '__exit__'
    
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