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Home/ Questions/Q 7829135
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T10:38:04+00:00 2026-06-02T10:38:04+00:00

I took this code straight from the w3 schools example, however, outside of their

  • 0

I took this code straight from the w3 schools example, however, outside of their “Tryit Editor” it doesn’t work for me. Any ideas?

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script>
    <script type="text/javascript">
        $(document).ready(function () {
            $("button").click(function () {
                $.getJSON("http://w3schools.com/jquery/demo_ajax_json.js", function (result) {
                    $.each(result, function (i, field) {
                        $("div").append(field + " ");
                    });
                });
            });
        });
    </script>
</head>
<body>
    <button>Get JSON data</button>
    <div></div>
</body>
</html>
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  1. Editorial Team
    Editorial Team
    2026-06-02T10:38:10+00:00Added an answer on June 2, 2026 at 10:38 am

    You can only make an AJAX request to a location on the current domain, unless you are requesting a JSONP response. This is a security feature in all browsers. Google for ‘Same origin policy’ and ‘Cross site scripting’ for more info.

    The workaround is to use a server-side proxy to request the data from the external domain, then use jQuery to query your local proxy.

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