Question

I tried doing this in C and it crashes:

int nValue=1;   
void* asd;  
asd[0]=&nValue;

With the following error:

*error C2036: 'void**' *: unknown size  
error C2100: illegal indirection*

Can I use a void pointer in C as an array?

And if I can, what is the correct way to do so?

Answer 1

you can write like this:

int main()
{
    int iv = 4;
    char c = 'c';
    void *pv[4];
    pv[0] = &iv;
    pv[1] = &c;

    printf("iv =%d, c = %c", *(int *)pv[0], *(char *)pv[1]);
    return 0;
}