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Home/ Questions/Q 8911329
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T03:54:56+00:00 2026-06-15T03:54:56+00:00

i tried: int i = 5; object o1 = i; // boxing the i

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i tried:

int i = 5;
object o1 = i; // boxing the i into object (so it should be a reference type)
object o2 = o1; // set object reference o2 to o1 (so o1 and o2 point to same place at the heap)

o2 = 8; // put 8 to at the place at the heap where o2 points

after running this code, value in o1 is still 5, but i expected 8.

Am I missing something?

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  1. Editorial Team
    Editorial Team
    2026-06-15T03:54:57+00:00Added an answer on June 15, 2026 at 3:54 am

    That’s not how variables in C# work. It has nothing to do with boxing value types.

    Consider this:

    object o1 = new object();
    object o2 = o1;
    
    o2 = new object();
    

    Why would you expect o1 and o2 to contain a reference to the same object? They are the same when you set o2 = o1, but once you set o2 = new object(), the value (the memory location pointed to by the variable) of o2 changes.

    Maybe what you’re trying to do can be done like this:

    class Obj {
        public int Val;
    }
    
    void Main() {
        Obj o1 = new Obj();
        o1.Val = 5;
        Obj o2 = o1;
        o2.Val = 8;
    }
    

    At the end of Main, the Val property of o1 will contain 8.

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