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Home/ Questions/Q 9232845
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T06:24:36+00:00 2026-06-18T06:24:36+00:00

I tried of writing those vars and stuck them back into the render function

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I tried of writing those vars and stuck them back into the render function of Django shortcut which means write at least 4 times for just one var.

For instance:

def foo(request):

  bar = request.GET.get('bar')
  bar += 1
  result = {'bar':bar}
  render('parrot.html', result)

It’s OK when I write just one var, but when comes to 20 more GET vars, that’s totally a disaster.

Any suggestion?

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  1. Editorial Team
    Editorial Team
    2026-06-18T06:24:37+00:00Added an answer on June 18, 2026 at 6:24 am

    First, the type of the return value of request.GET.get('bar') is either str or NoneType instead of int, thus you can’t simply add it by 1.

    Second, remember there is ‘no magic’, I’d like to rewrite the code like the following, but there are still four occurrences of bar

    def foo(request):
        try:
            bar = 1 + int(request.GET['bar'])
        except:
            bar = 0
        return render('parrot.html', {'bar':bar})
    

    If you don’t like this sort of verbosity, just abstract the try...except part to a helper such as get_int. When there are 20 or more vars to operate on, you may need higher level of abstraction such as Django forms…

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