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Home/ Questions/Q 3320222
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T22:55:03+00:00 2026-05-17T22:55:03+00:00

I tried profiling my application with OProfile recently. The data gathered is already very

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I tried profiling my application with OProfile recently. The data gathered is already very valuable to me, but I’m having difficulties with its precise interpretation. After running my app with oprofile set up and running, I generated the report and got:

root@se7xeon:src# opreport image:test -l -t 1
Overflow stats not available
CPU: P4 / Xeon with 2 hyper-threads, speed 3191.66 MHz (estimated)
Counted GLOBAL_POWER_EVENTS events (time during which processor is not stopped) with a unit mask of 0x01 (mandatory) count 750000
samples % symbol name
215522 84.9954 cci::Image::interpolate(unsigned char*, cci::Matrix const&) const
17998 7.0979 cci::Calc::diff(unsigned char const*, unsigned char const*)
13171 5.1942 cci::Image::getIRect(unsigned char*, int, int) const
5519 2.1765 cci::Image::getFRect(unsigned char*, double, double) const

Okay, so my interpolation function is responsible for 84% of the application’s (too long) execution time. Seems a good idea to look into it then:

root@se7xeon:src# opannotate image:test –source
[…]

/* cci::Image::interpolate(unsigned char*, cci::Matrix<cci::Point2DF> const&) const total: 215522   84.9954 */  
1392  0.5529 :void Image::interpolate(CCIPixel *output, const Matrix<Point2DF> &inputPoints) const throw()  
4  0.0016 :{  
[...]  
:                col0 = static_cast<int>(point[idx].x);  
3  0.0012 :      col1 = col0+1;  
629  0.2498 :    row0 = static_cast<int>(point[idx].y);  
385  0.1529 :    row1 = row0+1;  
56214 22.3266 :  if (col0 < 0 || col1 >= m_width || row0 < 0 || row1 >= m_height)  
:                {  
:                        col0 = row0 = col1 = row1 = 0;  
:                }  

If I understand correctly, the if conditional is responsible for over 22% of the program’s execution time. The opening brace and the function declaration seem to take time, is that supposed to correspond to the function call overhead (“push parameters on stack, jump, pop parameters” sequence)?

I changed some things in the source (related to a later bottleneck because I had no idea how to optimize an if), recompiled, ran through oprofile again (not forgetting opcontrol –reset). Now the annotated code looks like this in the same place:

6  0.0024 :     curPx = point[idx].x;  
628  0.2477 :   curPy = point[idx].y;  
410  0.1617 :   col0 = static_cast<int>(curPx);  
57910 22.8380 : col1 = col0+1;  
:               row0 = static_cast<int>(curPy);  
:               row1 = row0+1;  
:               if (col0 < 0 || col1 >= m_width || row0 < 0 || row1 >= m_height)  
:               {  
:                   col0 = row0 = col1 = row1 = 0;  
:               }  

This time the if takes basically no time at all (?), the most expensive instruction is “col1 = col0 + 1”, and the whole time-taking block seems to have shifted upwards. How can this be? Can this be trusted at all to pinpoint bottlenecks in the source?

An another point of doubt for me is that when I set up opcontrol, I entered the traced event as GLOBAL_POWER_EVENTS, with the number of samples being 750k. In the output, the interpolation function seems to take 84%, but the number of samples recorded inside it is only a little bit above 200k. That isn’t even 50% of the requested number. Am I to understand that the remaining ~500k samples was taken by applications not listed in the output (kernel, Xorg, etc.)?

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  1. Editorial Team
    Editorial Team
    2026-05-17T22:55:04+00:00Added an answer on May 17, 2026 at 10:55 pm

    When profiling optimized code you really cannot rely on accurate source code lines. The compiler moves stuff around far too much.

    For an accurate picture you will need to look at the code disassembler output.

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