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Home/ Questions/Q 3600802
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T20:32:28+00:00 2026-05-18T20:32:28+00:00

I tried running the following scheme code: (define affiche-gagnant (lambda (j1 j2 g1 g2)

  • 0

I tried running the following scheme code:

(define affiche-gagnant 
  (lambda (j1 j2 g1 g2)
    (begin 
      (display "Le gagnant est : ")
      (display 
       (cond ((> g1 g2) j1) 
             ((< g1 g2) j2) 
             (else (begin (display "personne. ") (display j1) (display " et ") (display j2) (display " sont exaequos. "))))))))

But I get the following output:

Le gagnant est : personne. Alper et Ezgi sont exaequos. #<void>

Where did the #void come from? How do I get rid of it?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T20:32:29+00:00Added an answer on May 18, 2026 at 8:32 pm

    Oops, wrong answer. You have an extra display:

    (define affiche-gagnant 
      (lambda (j1 j2 g1 g2)
        (begin 
          (display "Le gagnant est : ")
           (cond ((> g1 g2) (display j1)) 
                 ((< g1 g2) (display j2)) 
                 (else (begin (display "personne. ") (display j1) (display " et ") (display j2) (display " sont exaequos. ")))))))
    

    Should work.

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