Question

I tried strftime( ) to get a formatted time-stamp.

char ft[ 256 ]; struct tm *tmp; strftime( ft, 256, '%D - %T', tmp ); 

My problem is that I get ’13/02/60 – 03:07:-17958194′ as a result. Is there a way to display the seconds properly? (I’m using Mac OS X and gcc)

Answer 1

You’re using an uninitialized value in the code that you’ve posted, which would explain why you have this problem. The following code results in what you’re looking for:

#include <stdio.h> #include <time.h>  int main(int argc, char *argv[]) {   char ft[256];   struct tm *tmp;   time_t curtime;    time(&curtime);   tmp = localtime(&curtime);    strftime(ft, 256, '%D - %T %s', tmp);   printf('%s\n', ft);    return(0); } 

Then, compile and run the example:

cc -o time_ex time_ex.c ./time_ex 02/26/09 - 11:26:34 1235665594 

ETA: Drop the %s if you just want the local time without UNIX time after it, of course.