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Home/ Questions/Q 8419647
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T02:40:19+00:00 2026-06-10T02:40:19+00:00

I tried this code: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing;

  • 0

I tried this code:

    using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Xml;

namespace WindowsFormsApplication1
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            string xmlString = System.IO.File.ReadAllText(@"d:\adilipman1937067724.xml");

            XmlDocument doc = new XmlDocument();
            doc.Load(xmlString);
            string t = doc.InnerText;

            textBox1.Text = t;
        }
    }
}

But getting error:

error: Invalid URI: The Uri string is too long. The file im trying to read is xml of chat history in my messenger with my brother. The file size is: 492kb .

Getting error exception message:

System.UriFormatException was unhandled
  Message=Invalid URI: The Uri string is too long.
  Source=System
  StackTrace:
       at System.Uri.CreateThis(String uri, Boolean dontEscape, UriKind uriKind)
       at System.Uri..ctor(String uriString, UriKind uriKind)
       at System.Xml.XmlResolver.ResolveUri(Uri baseUri, String relativeUri)
       at System.Xml.XmlUrlResolver.ResolveUri(Uri baseUri, String relativeUri)
       at System.Xml.XmlTextReaderImpl..ctor(String url, XmlNameTable nt)
       at System.Xml.XmlDocument.Load(String filename)
       at WindowsFormsApplication1.Form1.button1_Click(Object sender, EventArgs e) in D:\C-Sharp\AnimatedGifEditor\WindowsFormsApplication1\WindowsFormsApplication1\Form1.cs:line 25
       at System.Windows.Forms.Control.OnClick(EventArgs e)
       at System.Windows.Forms.Button.OnClick(EventArgs e)
       at System.Windows.Forms.Button.OnMouseUp(MouseEventArgs mevent)
       at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks)
       at System.Windows.Forms.Control.WndProc(Message& m)
       at System.Windows.Forms.ButtonBase.WndProc(Message& m)
       at System.Windows.Forms.Button.WndProc(Message& m)
       at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
       at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
       at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
       at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg)
       at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(IntPtr dwComponentID, Int32 reason, Int32 pvLoopData)
       at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context)
       at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context)
       at System.Windows.Forms.Application.Run(Form mainForm)
       at WindowsFormsApplication1.Program.Main() in D:\C-Sharp\AnimatedGifEditor\WindowsFormsApplication1\WindowsFormsApplication1\Program.cs:line 18
       at System.AppDomain._nExecuteAssembly(RuntimeAssembly assembly, String[] args)
       at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args)
       at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
       at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
       at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state, Boolean ignoreSyncCtx)
       at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state)
       at System.Threading.ThreadHelper.ThreadStart()
  InnerException: 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T02:40:20+00:00Added an answer on June 10, 2026 at 2:40 am

    Couple of things.

    Easiest way to see whether the format of an xml document is correct is to open it in Internet Explorer. It’ll tell you if there are problems.

    An easy way to view the contents of an xml document, with all xml tags stripped away:

    XmlDocument doc = new XmlDocument();
    doc.Load(@"C:\tt.xml");
    string xmlString = doc.InnerText;
    

    The above method will also tell you if there problems with your xml document.

    The syntax of your call looks correct, so I assume there must be a problem with your xml document. Fix that first (one problem at a time!), then have another go.

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